Answered

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How much work is needed to transfer 767.1 kC of charge in one hour through a potential rise of 567.78 V ?

Sagot :

The change in potential energy ΔU of a system where a charge q moves through a potential difference ΔV is:

[tex]\Delta U=q\Delta V[/tex]

The work needed to move a charge q through a potential difference ΔV is the same as the change in potential energy of the system. Then, replace q=767.1kC and ΔV=567.78V to find the work needed to complete the described process:

[tex]\begin{gathered} \Delta U=q\Delta V \\ =(767.1kC)(567.78V) \\ =435,544kJ \end{gathered}[/tex]

Therefore, the amount of work needed to complete such a process is approximaely 435,544 kiloJoules.

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