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For the graph shown to the right, find (a) AB tó the nearest tenth and (b) the coordinates of the midpoint of AB.(a) AB=

For The Graph Shown To The Right Find A AB Tó The Nearest Tenth And B The Coordinates Of The Midpoint Of ABa AB class=

Sagot :

[tex]\begin{gathered} A=(-4,-4) \\ B=(6,-6) \\ \text{hence} \\ \text{distanceAB}=\sqrt[]{(-6-(-4))^2+(6-(-4))^2} \\ \text{distanceAB}=\sqrt[]{(-6+4)^2+(6+4)^2} \\ \text{distanceAB}=\sqrt[]{(-2)^2+10^2} \\ \text{distanceAB}=\sqrt[]{4+100} \\ \text{distanceAB}=\sqrt[]{104} \\ \text{distanceAB}=10.2 \end{gathered}[/tex][tex]\begin{gathered} \text{midpoint M} \\ M=(\frac{6-4}{2},\frac{-6-4}{2}) \\ M=(\frac{2}{2},\frac{-10}{2}) \\ M=(1,-5) \end{gathered}[/tex]

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