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Hello, I need quick help with this math question please

Hello I Need Quick Help With This Math Question Please class=

Sagot :

Given:

[tex]3(x-9)^2=21[/tex]

Simplify:

[tex]3x^2-54x+222=0[/tex]

Use the quadratic formula to solve for the values of x.

a = 3

b = -54

c = 222

[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex][tex]x=\frac{-(-54)\pm\sqrt[]{(-54)^2-4(3)(222)}}{2(3)}[/tex][tex]x=\frac{54\pm\sqrt[]{2916-2664}}{6}[/tex][tex]x=\frac{54\pm\sqrt[]{252}}{6}[/tex]

Solve for x (1)

[tex]x=\frac{54+\sqrt[]{252}}{6}[/tex][tex]x=\frac{54}{6}+\frac{6\sqrt[]{7}}{6}[/tex][tex]x=9+\sqrt[]{7}[/tex]

Solve for x (2)

[tex]x=\frac{54-\sqrt[]{252}}{6}[/tex][tex]x=\frac{54}{6}-\frac{6\sqrt[]{7}}{6}[/tex][tex]x=9-\sqrt[]{7}[/tex]

Therefore, the answer would be C.

[tex]x=9\pm\sqrt[]{7}[/tex]

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