Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

triangle ABC has been reflected over line AC to from quadrilateral ABCD Using what you know about grid information, side lengths and angle measures, label as many sides lengths and angles measures as you can.

Triangle ABC Has Been Reflected Over Line AC To From Quadrilateral ABCD Using What You Know About Grid Information Side Lengths And Angle Measures Label As Many class=

Sagot :

You have that the triangle ACD is a reflection of triangle ABC arounf line AC. This means that line AD is a relfection of line AB, and line CD is a relflection of line BC.

If AD is reflection of AB, then AD has the same length as AB, hence:

AD = AB = 2.7

if CD is reflection of BC, then:

CD = BC = 3.2

Now, due to triangle ACD is reflection of ABC, angle ∠ACD (up right side) must be equal to ∠ABC (left down side), then:

∠ACD = ∠ABC = 64.3°

Furthermore, you can notice that angle ∠BAD is equal to angle ∠BCD. And the sum of all angles inside the figure must be equal to 360° (because it is a figure of four sides). Hence, you have:

∠BAD = ∠BCD

∠BAD + ∠BDC + 64.3° + 64.3° = 360°

∠BAD + ∠BAD + 64.3° + 64.3° = 360°

2∠BAD + 64.3° + 64.3° = 360°

2∠BAD + 128.6° = 360°

2∠BAD = 360° - 128.6°

2∠BAD = 231.4°

∠BAD = 231.4°/2

∠BAD = 115.7°

Hence, angle ∠BAD = ∠BCD is equal to 115.7°

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.