Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
hello
the question here request we find the equation of line passing through point (-1, 2)
the first equation given is
[tex]y=-\frac{1}{3}x+6[/tex]passing through points (-1, 2)
equation of line is given as
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ m=-\frac{1}{3} \\ \end{gathered}[/tex]the points are (-1, 2)
[tex]\begin{gathered} x_1=-1 \\ y_1=2 \end{gathered}[/tex]now, let's substitute the values into the equation above
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-2=-\frac{1}{3}(x-(-1)) \\ y-2=-\frac{1}{3}(x+1) \\ y-2=-\frac{(x+1)}{3} \\ \text{cross multiply both sides} \\ 3(y-2)=-x-1 \\ 3y-6=x-1 \\ 3y=-x-1 \\ \text{divide both sides by the coeffiecient of y which is 3} \\ \frac{3y}{3}=\frac{-x-1}{3} \\ y=\frac{-x-1}{3} \\ y=-\frac{x}{3}-\frac{1}{3} \end{gathered}[/tex]
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
