Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Given:
f = -20 cm
height, h = 25 cm
distance = 50 cm
Let's find the size and position of the birds image.
Apply the formula:
[tex]\frac{1}{f}=\frac{1}{v}+\frac{1}{u}[/tex]Where:
f = -20 cm
u = - 50 cm
Rewrite the formula and solve for v.
[tex]\begin{gathered} \frac{1}{v}=\frac{1}{f}-\frac{1}{u} \\ \\ \frac{1}{v}=\frac{1}{20}-\frac{1}{-50} \\ \\ \frac{1}{v}=\frac{1}{20}+\frac{1}{50} \\ \\ \frac{1}{v}=\frac{5+2}{100} \\ \\ \frac{1}{v}=\frac{7}{100} \\ \\ v=\frac{100}{7}=14.28\text{ m/s} \end{gathered}[/tex]Now, let's find the height of the image:
[tex]\begin{gathered} \frac{h_i}{h_o}=\frac{-v}{u} \\ \\ \frac{hi}{25}=\frac{-14.28}{-50} \\ \\ hi=\frac{14.28*25}{50} \\ \\ h_i=7.14\text{ cm} \end{gathered}[/tex]We can see the image height is smaller.
The formed image is virtual and erect.
ANSWER:
• The image height is smaller.
,• The formed image is virtual and erect.
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.
