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Sagot :
Given
Kiran bought a wedge with central of angle of pi/2 radians and radius 3 inches.
To find: What is the area of the top surface of the wedge?
Explanation:
It is given that,
Kiran bought a wedge with central of angle of pi/2 radians and radius 3 inches.
That implies,
[tex]\begin{gathered} \theta=\frac{\pi}{2}\text{ }radians\text{ }=90\degree \\ r=3\text{ }inches \end{gathered}[/tex]Then, the area of the top surface of the wedge is,
[tex]\begin{gathered} Area\text{ }of\text{ }the\text{ }top\text{ }surface\text{ }of\text{ }the\text{ }wedge=\frac{\theta}{360}\times\pi r^2 \\ =\frac{90}{360}\times\pi(3)^2 \\ =\frac{1}{4}\times9\pi \\ =\frac{9}{4}\pi\text{ }square\text{ }inches \end{gathered}[/tex]Hence, the area of the top surface of the wedge is (9/4)π square inches.
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