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=024- 9.com9.com3. A stone is dropped from a bridge and hits the water at a velocity of 68.6m/s. Howlong does it take for the stone to hit the water? (a=9.8m/s?)A jai-lai ball is traveling at 80.0ft/s. The ball is hit in the opposite direction afinal velocity is -98.2ft/s. What was the acceleration if the change in veloci-Only 3.0ms?#3

024 9com9com3 A Stone Is Dropped From A Bridge And Hits The Water At A Velocity Of 686ms Howlong Does It Take For The Stone To Hit The Water A98msA Jailai Ball class=

Sagot :

The velocity of the stone when it hits the water, i.e., the final velocity of the stone, v=68.6 m/s

The acceleration of the stone, a=9.8 m/s²

As the stone was dropped (not thrown), the initial velocity of the stone, u=0 m/s

From one of the equations of the motion,

[tex]v=u+at[/tex]

Where t is the time interval in which the stone hits the water.

On rearranging the above equation,

[tex]t=\frac{v-u}{a}[/tex]

On substituting the known values in the above equation,

[tex]\begin{gathered} t=\frac{68.6-0}{98} \\ =0.7\text{ s} \end{gathered}[/tex]

Therefore the stone hits the water 0.7 seconds after it is dropped.