Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
[tex]\begin{equation*} 448.1 \end{equation*}[/tex]
1) Given that my car gets 22 miles per gallon, and I drive 498 miles I'll need to make reference to the emission rate of CO2 my car has: 19.8 lbs/gallon.
2) So, we can write out the following ratios. Firstly, we need to figure out how many gallons of gas were needed to drive 498 miles
[tex]\begin{gathered} 22miles--------1g \\ 498----------x \\ 22x=498 \\ x=\frac{498}{22} \\ x=22.63gallons \end{gathered}[/tex]Now, we can write out the following relationship:
[tex]\begin{gathered} 19.8lbs---1gallon \\ y------22.63 \\ \frac{19.8}{y}=\frac{1}{22.63} \\ \\ y=448.074\approx448.1\:\frac{lbs}{gallon} \end{gathered}[/tex]
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
