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Sagot :
We are to find the equation of a line using slope-intercept form
Given, slope = -1 and point (8,-8)
The slope-intercept equation is given to be
[tex]y=mx+c[/tex]From the point (8, -8)
x = 8, y = -8
Substituting the values of x and y from into the equation
slope, m = -1
We have
[tex]-8=(-1)(8)+c[/tex]Simplifying this we get
[tex]\begin{gathered} -8=-8+c \\ -8+8=c \\ c=0 \end{gathered}[/tex]Hence, c = 0
Substituting the value of c and m into the slope-intercept equation
We get
[tex]y=-1x+0[/tex]The equation become
[tex]y=-x[/tex]
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