Answered

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Suppose two trains leave Mexico City at the same time. One travels east and the other travels west at a speed that is 10mph slower. In 1.5 hours, the trains are 171 miles apart. Find the speed of the train. Set up a table to help you set up the equation

Sagot :

Answer:

63 mph and 53 mph

Explanation:

We can represent the situation as:

Therefore, if we call x the speed of the train that travels east, (x-10) is the speed of the train that travels west.

Then, after 1.5 hours, they are at a distance of 171 miles and they are getting apart at a speed equal to the sum of both speeds, so we can write the following equation:

[tex]\begin{gathered} \text{speed = }\frac{dis\tan ce}{time} \\ x+(x-10)=\frac{171}{1.5} \end{gathered}[/tex]

So, solving for x, we get:

[tex]\begin{gathered} x+x-10=114 \\ 2x-10=114 \\ 2x-10+10=114+10 \\ 2x=124 \\ \frac{2x}{2}=\frac{124}{2} \\ x=62 \end{gathered}[/tex]

Therefore, the speed of the first train was 63 mph and the speed of the second train was 10 mph slower, so it was 53 mph.

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