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Sagot :
We know that
• The initial velocity is 198 km/hr.
,• The acceleration is 2m/s^2.
,• The time elapsed is 3.40 seconds.
We have to find the distance covered. To do that, use the following formula that relates to initial velocity, time, acceleration, and distance.
[tex]\begin{gathered} d=v_0t+\frac{1}{2}at^2 \\ \end{gathered}[/tex]But, first, we have to transform 198 km/hr to m/s. We know that 1 km equals 1000 m, and 1 hr equals 3600 seconds.
[tex]198\cdot\frac{km}{hr}\cdot\frac{1hr}{3600\sec}\cdot\frac{1000m}{1\operatorname{km}}=\frac{198\cdot1000}{3600}\cdot\frac{m}{s}=55(\frac{m}{s})[/tex]Once we transform the speed, we are able to find the distance traveled.
[tex]\begin{gathered} d=55(\frac{m}{s})\cdot3.4\sec +\frac{1}{2}\cdot2(\frac{m}{s^2})\cdot(3.4\cdot\frac{m}{s})^2 \\ d=187m+11.56m \\ d=198.56m \end{gathered}[/tex]Therefore, the object traveled 198.56 meters.
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