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write the equation of the line in standard form. slope of 2/3 and passing through the points (-5, 1)

Sagot :

Answer:

Explanation:

The standard form of a linear equation is

[tex]Ax+By=C[/tex]

However, it is a lot easier if we find the equation in slope-intercept form

[tex]y=mx+b[/tex]

and then rearrange the above equation to write it in standard form.

We are told that the slope of the line is 2/3 which means m = 2/3; therefore, the above equation becomes

[tex]y=\frac{2}{3}x+b[/tex]

Moreover, fro the point (-5, 1) we know that when x = -5, then y = 1; therefore, the above equation gives

[tex]1=\frac{2}{3}(-5)+b[/tex]

Simplifying the above gives

[tex]1=-\frac{10}{3}+b[/tex]

adding 10/3 to both sides gives

[tex]1+\frac{10}{3}=-\frac{10}{3}+b+\frac{10}{3}[/tex][tex]\begin{gathered} \frac{3}{3}+\frac{10}{3}=b \\ \\ \end{gathered}[/tex][tex]\therefore b=\frac{13}{3}[/tex]

With the value of b in hand, we write the slope-intercept of the equation:

[tex]y=\frac{2}{3}x+\frac{13}{3}[/tex]

Now, to write the above in standard form, we multiply both sides by 3. This cancels out 3 in the denominator on the right-hand side and gives

[tex]3y=2x+13[/tex]

Finally, subtracting 2x from both sides gives

[tex]3y-2x=13[/tex]

Just shift the position of the terms on the left-hand the side and we get

[tex]\boxed{-2x+3y=13.}[/tex]

which is the standard form of our equation!

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