Answered

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The weights of the babies born in Martin County Hospital are normally distributed with a mean of 119 ounces and astandard deviation of 20 ounces. What percent of the babies have a birth weight between 59 and 179 ounces?

Sagot :

First, let's calculate the z-score corresponding to x = 59 and x = 179, using the formula below:

[tex]\begin{gathered} z_1=\frac{59-119}{20}=\frac{-60}{20}=-3\\ \\ z_2=\frac{179-119}{20}=\frac{60}{20}=3 \end{gathered}[/tex]

Now, let's look at the z-table for the probability corresponding to each value of z.

for z = -3, we have a probability of 0.0013.

For z = 3, we have a probability of 0.9987.

Calculating the interval between these values, we have:

[tex]P=0.9987-0.0013=0.9974=99.74\%[/tex]

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