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Write an equation of the line that passes through the given points. (0, -6), (8, -16)

Sagot :

SOLUTION

In this equation, we are meant to find the equation of the line that passes through the points ( 0, -6 ) and ( 8 , - 16 ).

( x 1 , y1 ) = ( 0, -6 )

( x 2 , y2 ) = ( 8 , - 16 )

We need to first get the gradient of the two points :

m = ( y2 - y 1 ) / ( x 2 - x 1 )

m = (- 16 - - 6 ) / ( 8 - 0)

m = -10 / 8

m = -5 / 4

Next , we use the equation of the line :

y - y1 = m ( x - x 1 )

y - - 6 = - 5/ 4 ( x - 0 )

y + 6 = - 5/ 4 x

Multiply through by 4 , we have :

4 ( y + 6 ) = -5 x

4y + 24 = -5 x

5 x + 4y + 24 = 0

CONCLUSION: The equation of the line is 5 x + 4y + 24 = 0.