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What is the new temperature ( 0C) of a 1.50 kg steel camping dish if it was heated from 15.0 0C by 61.0 kJ of heat.

What Is The New Temperature 0C Of A 150 Kg Steel Camping Dish If It Was Heated From 150 0C By 610 KJ Of Heat class=

Sagot :

Given:

The mass of steel is m = 1.5 kg

The initial temperature of the steel dish is

[tex]T_i=15^{\circ}C[/tex]

The heat supplied to the steel dish is Q = 61 kJ

The specific heat capacity of steel is c = 452 J/kg deg C

To find: The final temperature of the steel dish, T_f.

Explanation:

The formula to calculate the final temperature of the steel dish is

[tex]\begin{gathered} Q=mc(T_f-T_i) \\ T_f=\frac{Q}{mc}+T_i \end{gathered}[/tex]

Substituting the values, the final temperature of the steel dish will be

[tex]\begin{gathered} T_f=\frac{61\times10^3\text{ J}}{1.5kg\times452\frac{J}{kg^{\circ}C}\text{ }}+15 \\ =104.97^{\circ}C \end{gathered}[/tex]

Final Answer: The new temperature of the steel dish is 104.97 degrees Celsius.

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