Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

using the distance formula, write an equation of the parabola given focus (0,-3) and directrix y=3

Sagot :

Recalling the definition of a parabola:

Parabola: A parabola is a curve where any point is at an equal distance from

1) a fixed point (f₁,f₂) (the focus ), and

2) fixed straight line Ax+By+C=0 (the directrix).

Therefore, a point (x₀,y₀) is on the parabola iff:

[tex]\sqrt[]{(x_0-f_1)^2+(y_0_{}-f_2)^2}=|\frac{Ax_0+By_0+C}{\sqrt[]{A^2+B^2}}|[/tex]

Now, if the directrix is y=3 and the focus is (0,-3), then (x₀,y₀) is on the parabola iff:

[tex]\sqrt[]{(x_0-0)^2+(y_0-(-3))^2}=|y_0-3|[/tex]

Raising the equation to power 2 and solving for y₀ we get:

[tex]\begin{gathered} x^2_{0^{}}+(y_0+3)^2=(y_0-3)^2 \\ x^2_0+y^2_0+6y_0+9=y^2_0-6y_0+9 \\ x^2_0=-12y_0 \\ y_0=-\frac{x^2_0}{12} \end{gathered}[/tex]

Therefore the equation of the parabola with focus (0,-3) and directrix y=3 is:

[tex]y=-\frac{x^2}{12}[/tex]

View image RahmaU610351