find the line equation perpendicular to x = -5 and passing through the point (1,-2)

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04-11-2022
Mathematics

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find the line equation perpendicular to x = -5 and passing through the point (1,-2)

Sagot :

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OvadiaO355207 OvadiaO355207 · Answer 1 · 2022-11-04T05:50:29-04:00

Given:

The line is perpendicular to x =-5.

and passing through the point ( 1, -2).

The line x= -5 is parallel to y- axis and any line parallel to y-axis has undefined slope.

So, the line perpendicular to the line x=-5 will be 0.

The slope point form of equation of line is,

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \text{here, m= slope =0 and (x}_1,y_1)=(1,-2) \\ y-(-2)\text{ = (0) (x-1)} \\ y+2=0 \\ y=-2 \end{gathered}[/tex]

Hence, the equation of line perpendicular to x=-5 and passing through point (1,-2) is y=-2.

Sagot :

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