Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

find the line equation perpendicular to x = -5 and passing through the point (1,-2)

Sagot :

Given:

The line is perpendicular to x =-5.

and passing through the point ( 1, -2).

The line x= -5 is parallel to y- axis and any line parallel to y-axis has undefined slope.

So, the line perpendicular to the line x=-5 will be 0.

The slope point form of equation of line is,

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \text{here, m= slope =0 and (x}_1,y_1)=(1,-2) \\ y-(-2)\text{ = (0) (x-1)} \\ y+2=0 \\ y=-2 \end{gathered}[/tex]

Hence, the equation of line perpendicular to x=-5 and passing through point (1,-2) is y=-2.

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.