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f(n) =n^3 - 1 help me please!!!!!

Sagot :

Given that

f(n) = n^3 -1

when

n = 1

f(n) = 1^3 - 1

= 1 - 1

= 0

when

n = 2

f(n) = 2^3 - 1

= 8 - 1

= 7

when

n = 3

f(n) = 3^3 - 1

= 27 - 1

= 26

when

n = 4

f(n) = 4^3 - 1

= 64 - 1

= 63