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factoring completely i am stuck, I got x to the power of 2 -4x-21

Factoring Completely I Am Stuck I Got X To The Power Of 2 4x21 class=

Sagot :

The given expression is

[tex]11x^2-44x-231[/tex]

Since the greatest common factor of 11, 44, 231 is 11, then divide each term by 11 to take it as a common factor

[tex]11(\frac{11x^2}{11}-\frac{44x}{11}-\frac{231}{11})=11(x^2-4x-21)[/tex]

Now, we will factorize the trinomial into 2 factors

Since

[tex]\begin{gathered} x^2=(x)(x) \\ -21=(-7)(3) \\ -4x=(-7)(x)+(3)(x) \end{gathered}[/tex]

Then the 2 factors are (x - 7)(x + 3)

[tex]11(x^2-4x-21)=11(x-7)(x+3)[/tex]

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