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Find the image of point A (6, -12) using the rule(x, y) – > (x – 4, y + 7)O A' (3,0)O A' (2,-5)O A' (-4,7)0 A (-2,5)

Find The Image Of Point A 6 12 Using The Rulex Y Gt X 4 Y 7O A 30O A 25O A 470 A 25 class=

Sagot :

The original point is:

[tex]A(6,-12)[/tex]

The first step will be to identify the x and y values:

[tex]\begin{gathered} x=6 \\ y=-12 \end{gathered}[/tex]

And the second step will be to apply the given rule.

The rule for the transformation is:

[tex](x,y)\longrightarrow(x-4,y+7)[/tex]

This tells us that to find the image point we have to subtract 4 to the x value and add 7 to the y value.

We apply the rule to the original point:

[tex](6,-12)\longrightarrow(6-4,-12+7)[/tex]

And solving the operations:

[tex](6,-12)\longrightarrow(2,-5)[/tex]

We have found the image point:

[tex]A^{\prime}(2,-5)[/tex]

Answer:

[tex]A^{\prime}(2,-5)[/tex]

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