Answered

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Gavin is working two summer jobs, making $20 per hour lifeguarding and making $6per hour walking dogs. In a given week, he can work no more than 10 total hours andmust earn at least $go. If a represents the number of hours lifeguarding and yrepresents the number of hours walking dogs, write and solve a system of in qualitiesgraphically and determine one possible solution.

Gavin Is Working Two Summer Jobs Making 20 Per Hour Lifeguarding And Making 6per Hour Walking Dogs In A Given Week He Can Work No More Than 10 Total Hours Andmu class=

Sagot :

Let x be the number of hours Gavin works as lifeguarding and y be the number of hours he works walking dogs, then we can set the following system of inequalities:

[tex]\begin{gathered} x+y\le10, \\ 20x+6y\ge90. \end{gathered}[/tex]

Solving the first inequality for y, we get:

[tex]\begin{gathered} x+y\le10, \\ y\le10-x\text{.} \end{gathered}[/tex]

Solving the second inequality for y we get:

[tex]\begin{gathered} 20x+6y\ge90, \\ 6y\ge90-20x, \\ y\ge15-\frac{20}{6}x\text{.} \end{gathered}[/tex]

Answer: Inequality 1

[tex]y\le10-x\text{.}[/tex]

Inequality 2

[tex]y\ge15-\frac{20}{6}x_{}\text{.}[/tex]

Now, to find a solution we overlap the above graphs:

A possible solution is x=5 and y=4.

View image NainaO380512
View image NainaO380512
View image NainaO380512
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