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What is the equation of the line that passes through the point (-6, -8) and has aslope of 1/3?

Sagot :

Answer:

x-3y=18

Explanation:

To determine the equation of the line, we use the point-slope form

[tex]y-y_1=m(x-x_1)[/tex]

Given that:

[tex]m=\frac{1}{3},(x_{1,}y_1)=(-6,-8)[/tex]

We therefore have:

[tex]y-(-8)=\frac{1}{3}(x-(-6))[/tex]

We can then simplify:

[tex]\begin{gathered} y+8=\frac{1}{3}(x+6) \\ 3(y+8)=x+6 \\ 3y+24=x+6 \\ 3y-x=6-24 \\ 3y-x=-18 \\ x-3y=18 \end{gathered}[/tex]

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