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I need help on question 8 this is a non graded practice assignment

I Need Help On Question 8 This Is A Non Graded Practice Assignment class=

Sagot :

EXPLANATION

Since we have the expression y= (2/3)x + 1 and we need a parallel line passing through (-6,-1), we can asseverate that the new line will have the same slope but a different y-intercept.

Therefore, we have the new expression for the parallel line:

y=(2/3)x + b

Now, in order to get the value of b we can plug the point (-6,-1) as follows:

-1 = (2/3)(-6) + b

Multiplying numbers:

-1 = (-12/3) + b

Simplifying:

-1 = -4 + b

Adding +4 to both sides:

-1 + 4 = b

Adding numbers:

3 = b

The new value of the y-intercept is b=3, plugin in this value into y=(2/3)x + b give us the following expression:

y=(2/3)x + 3

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