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Sagot :
Given,
The force exerted, F=30 N
The distance for which the force is applied, s=6.0 m
The mass of the object, m=10 kg
The initial velocity, u=0 m/s
From Newton's second law,
[tex]F=ma[/tex]Thus the acceleration of the body is given by,
[tex]a=\frac{F}{m}[/tex]From the equation of the motion,
[tex]\begin{gathered} v^2=u^2+2as \\ \Rightarrow v^2=u^2+2\times\frac{F}{m}\times s \\ \Rightarrow v=\sqrt[]{u^2+2\times\frac{F}{m}\times s} \end{gathered}[/tex]On substituting the known values, the final velocity of the object is
[tex]\begin{gathered} v=\sqrt[]{0+2\times\frac{30}{10}\times6} \\ =6\text{ m/s} \end{gathered}[/tex]Thus the velocity of the object is 6 m/s
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