Given the system of equations;
[tex]\begin{gathered} y=x-1\ldots\ldots\ldots.\ldots\text{.}\mathrm{}\text{equation 1} \\ y=3x+1\ldots\ldots\ldots\ldots.equation\text{ 2} \end{gathered}[/tex]
To plot each of these lines on a graph, we would need to get some points such that we could use it to draw a straight line.
For equation 1;
[tex]\begin{gathered} \text{When x=0,} \\ y=0-1 \\ y=-1 \\ (0,-1) \\ \text{When y=0} \\ 0=x-1 \\ x=1 \\ (1,0) \end{gathered}[/tex]
Now, you draw a line joining these points together, we have;
Similarly, we would apply same to equation 2, we have;
[tex]\begin{gathered} \text{When x=0;} \\ y=3(0)+1 \\ y=1 \\ (0,1) \\ \text{When y=0;} \\ 0=3x+1 \\ x=-0.333 \\ (-0.333,0) \end{gathered}[/tex]
Then, we have its graph as;
Now, the combination of the two graphs is;
The solution of the system of equation is;
[tex](-1,-2)[/tex]
CORRECT OPTION: C
