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Sagot :
Let:
2x + 5y = 0 (1)
5x = 4y (2)
From (1) let's solve for x:
2x + 5y = 0
Subtract 5y from both sides:
2x + 5y - 5y = -5y
2x = -5y
Divide both sides by 2:
2x/2 = -5y/2
x = -5y/2 (3)
Replacing (3) into (2):
5x = 4y
5(-5y/2) = 4y
-25y/2 = 4y
Add 25y/2 to both sides:
-25y/2 + 25y/2 = 4y + 25y/2
33y/2 = 0
Multiply both sides by 2/33
y = 0
Finally replacing y into 3:
x = -5y/2
x = -5(0)/2
x = 0
So:
x = 0 and y = 0
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