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Find the equation for the line that passes through the (4,8) and intercepts with the X axis at -12.Make a sketch of its graph and label it “Line L”.Be sure to label the increments on the x and y axis of your graph.Create and write down an equation for the line parallel to Line L.Graph this perpendicular line.

Sagot :

The following diagram shows the graph of the line:

The line passes througt (4,8) and (-12,0) so the slope must be:

[tex]m=\frac{8-0}{4-(-12)}=\frac{8}{16}=\frac{1}{2}=0.5[/tex]

And the y-intercept of the graph is at (0,6) so the equation must be:

[tex]y=\frac{1}{2}x+6[/tex]

Any line with the same slope will be parallel to line L, for example:

[tex]y=\frac{1}{2}x+2[/tex]

As shown in the graph:

View image MythiasL206496
View image MythiasL206496
View image MythiasL206496