Since 15.3 L was used, we can convert this to mass using the density:
[tex]\begin{gathered} \rho=\frac{m}{V} \\ m=\rho\cdot V \end{gathered}[/tex]
Using the density of 0.755 g/mL, we need to convert the volume to mL, so:
[tex]V=15.3L=15300mL[/tex]
Now, using the volume and the density, we have:
[tex]m=\rho\cdot V=0.755g\/mL\cdot15300mL=11551.5g=1.15515\times10^4g\approx1.16\times10^4g[/tex]
So, the mass in grams is approximately 1.16 x 10⁴ g.
To convert to ounces, we can divide the value in grams by approximately 28.349523:
[tex]m=11551.5g=\frac{11551.5}{28.349523}oz=407.467\ldots oz\approx407oz[/tex]
So, the mass in ounces is approximately 407 oz.
