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Find the area of a dodecagon with a radius of 20 cm. round your answer to the nearest tenth.

Find The Area Of A Dodecagon With A Radius Of 20 Cm Round Your Answer To The Nearest Tenth class=

Sagot :

Answer:

The area is 1200cm²

Explanation:

To solve this problem, we need to find the side length. We can divide the dodecagon in isosceles triangles

The angle A we can calculate it, because the dodecagon is composed by 12 triangles like this. Since the sum of all angles A add up to a whole circle:

[tex]\angle A=\frac{360º}{12}=30º[/tex]

Since each triangle is an isosceles triangle, the two angles at the bottom are the same. Also, the sum of the internal angles of a triangle is 180º. Then:

[tex]\begin{gathered} A+B+B=180º \\ 30º+2B=180º \\ B=\frac{180º-30º}{2} \end{gathered}[/tex][tex]B=75º[/tex]

And finally, we can calculate x, which is half of the length of each side, using trigonometric relationships. In this case, we can use cosine:

[tex]\cos(B)=\frac{x}{r}[/tex]

Then:

• B = 75º

,

• r = 20cm

[tex]\begin{gathered} \cos(75º)=\frac{x}{20cm} \\ x\approx5.176cm \end{gathered}[/tex]

Then, the length of the side is twice x:

[tex]L=2\cdot5.18cm=10.35cm[/tex]

Now we can use the formula for the area of a dodecagon:

[tex]A=3(2+\sqrt{3})\cdot L^2[/tex]

Then:

[tex]A=3(2+\sqrt{3})(10.35)^2=1200cm^2[/tex]

The area is 1200 squared cm.

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