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Sagot :
We have a formula to find the interior angles sum of a regular polygons, we just need the number of sides
[tex](n-2)\times180[/tex]where n is the number of sides
We can modify the formula to know the measure of the angles, since they all measure the same, we will divide into the number of angles
So:
[tex]\frac{(n-2)\times180}{n}[/tex]now
Octagon
[tex]\begin{gathered} \frac{(8-2)\times180}{8} \\ \frac{6\times180}{8} \\ \frac{1080}{8} \\ =135 \end{gathered}[/tex]nonagon
[tex]\begin{gathered} \frac{(9-2)\times180}{9} \\ \frac{7\times180}{9} \\ =140 \end{gathered}[/tex]12-gon
[tex]\begin{gathered} \frac{(12-2)\times180}{12} \\ \frac{10\times180}{12} \\ =150 \end{gathered}[/tex]
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