Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
[tex]37.5+6x\leq70\rightarrow inequality[/tex]
therefore, the maximum number of foils Justin can have is 5
Explanation
Step 1
set the ineequality
Let x represents the number of foils
and
fee : $ 37.50
rate per foil = $ 6 per foil
total : no more than 70 ( so 70 or smaller)
so
total = fee+ ( cost of foils)
the cost of foils can be calculated using
cot of foils= rate*number of foils
replace
cost of foils= 6x
so, the total cost is
total = fee+ ( cost of foils)
total = 37.5+ 6x
[tex]total=37.5+6x[/tex]but, remember the total must be equal or smaller than 70
henc e
[tex]37.5+6x\leq70\rightarrow inequality[/tex]
Step 2
now, let's solve the inequality
[tex]\begin{gathered} 37.5+6x\leq70\rightarrow inequality \\ \text{subtract 37.5 in both sides} \\ 37.5+6x-37.5\leq70-37.5 \\ 6x\leq32.5 \\ \text{divide both sides by 6} \\ \frac{6x}{6}\leq\frac{32.5}{6} \\ x\leq5.41 \end{gathered}[/tex]as the unit is per foil, we need to use whole numbers, so the answer is
[tex]\begin{gathered} x\leq5.41 \\ x\leq5 \end{gathered}[/tex]therefore, the maximum number of foils Justin can have is 5
I hope this helps you
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
