Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A sample of SO2 gas has a volume of 18.0 L at a temperature of 35.0°C. At what temperature, in °C, will the gas have a volume of 13.0 L? (Hint: Convert ° C to K)

Sagot :

Answer

-50.6 °C

Explanation

Given:

Initial volume, V₁ = 18.0 L

Initial teperature, T₁ = 35.0°C = (35. + 273.15 K) = 308.15 K

Final volume, V₂ = 13.0 L

What to find:

The finaltemperatrure, T₂ in °C

Step-by-step solution:

The final temperature, T₂ can be calculated using Charle's lawfequation.

[tex]\begin{gathered} \frac{V_1}{T_1}=\frac{V_2}{T_2} \\ \\ \Rightarrow T_2=\frac{T_1V_2}{V_1} \end{gathered}[/tex]

Plugging the values of the given parameters into the formula, we have;

[tex]T_2=\frac{308.15\text{ }K\times13.0\text{ }L}{18.0\text{ }L}=222.55\text{ }K[/tex]

The final temperature, T₂ in °C = (222.55 - 273.15 ) = -50.6 °C

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.