Answered

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Explain what happens if you add 2 moles or 0.5 moles of Ca(OH)2 to a solution containing 2 moles of HCI

Explain What Happens If You Add 2 Moles Or 05 Moles Of CaOH2 To A Solution Containing 2 Moles Of HCI class=

Sagot :

Explanation:

The reaction of neutralization involved:

2 HCl (aq) + Ca(OH)2 (aq) => CaCl2 (aq) + 2 H2O (l) (completed and balanced)

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Data provided:

Case a)

2 moles HCl

2 moles Ca(OH)2

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Case b)

2 moles HCl

0.5 moles Ca(OH)2

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Procedure: Case a)

By stoichiometry,

2 HCl (aq) + Ca(OH)2 (aq) => CaCl2 (aq) + 2 H2O (l)

2 moles HCl ------- 1 mole Ca(OH)2

2 moles HCl ------- X

X = 2 moles HCl x 1 mole Ca(OH)2/2 moles HCl

X = 1 mole Ca(OH)2

For 2 moles of HCl, 1 mole of Ca(OH)2 is needed, but in case a) there are 2 moles of Ca(OH)2, so the limiting reactant is HCl.

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Procedure: Case b)

By stoichiometry,

2 HCl (aq) + Ca(OH)2 (aq) => CaCl2 (aq) + 2 H2O (l)

2 moles HCl ------- 1 mole Ca(OH)2

2 moles HCl ------- X

X = 2 moles HCl x 1 mole Ca(OH)2/2 moles HCl

X = 1 mole Ca(OH)2

For 2 moles of HCl, 1 mole of Ca(OH)2 is needed, but there are 0.5 moles of Ca(OH)2, so the limiting reactant is Ca(OH)2.

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