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A triangle with vertices A(2, -2), B(-1, -1) and C(0, 2) is reflected across the y-axis and then dilated by a factor of 3 with the origin as the center of dilation. What is the x-coordinate of the A''?

Sagot :

[tex]A^{\prime}^{\prime}(-6,-6)[/tex]

Explanation

Step 1

a) Plot the triangle

Step 2

now, do the transformations

Transformation 1

reflected across the y-axis:

The rule for a reflection over the y -axis is

[tex](x,y)\Rightarrow(-x,y)[/tex]

hence

[tex]\begin{gathered} A(2,-2)\Rightarrow reflected\text{ y-axis}\Rightarrow A^{\prime}(-2,-2) \\ B(-1,-1)\operatorname{\Rightarrow}reflected\text{y-ax}\imaginaryI\text{s}\operatorname{\Rightarrow}B^{\prime}(1,-1) \\ C(0,2)\operatorname{\Rightarrow}reflected\text{y-ax}\imaginaryI\text{s}\operatorname{\Rightarrow}C^{\prime}(0,2) \end{gathered}[/tex]

so

Step 3

transformation 2:

b)dilated by a factor of 3 with the origin as the center of dilation:

A dilation with scale factor k centered at the origin will take each point

and

[tex]P(x,y)\Rightarrow dilated\text{ \lparen}K\text{ is the factor\rparen}\Rightarrow P^{\prime}(kx,yx)[/tex]

so

in this case the factor is 3,hence

[tex]\begin{gathered} A^{\prime}(-2,-2)\Rightarrow dilated\text{ by a factor of 3}\Rightarrow A^{\prime}^{\prime}(-6,-6) \\ B^{\prime}(1,-1)\operatorname{\Rightarrow}dilated\text{ by a factor of 3}\Rightarrow B^{\prime}^{\prime}(3,-3) \\ C^{\prime}(0,2)\operatorname{\Rightarrow}dilated\text{ by a factor of 3}\Rightarrow C^{\prime^{\prime}}(0,6) \end{gathered}[/tex]

so,the coordinate of teh A'' is

[tex]A^{\prime}^{\prime}(-6,-6)[/tex]

I hope this helps you

View image AaimaK186934
View image AaimaK186934
View image AaimaK186934