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Sagot :
Take into account that the force can be written as follow:
[tex]F=\frac{\Delta p}{\Delta t}[/tex]where,
Δp: change in momentum = 17 kg.m/s
Δt: time interval at which the force change the momentum = 5 s
Replace the previous values of the parameters into the formula for F, and simplify:
[tex]F=\frac{17\operatorname{kg}\frac{m}{s}}{5s}=3.4\operatorname{kg}\frac{m}{s^2}=3.4N[/tex]Then, a force of 3.4N would be needed to change the momentum of an object 17 kgm/s in 5s.
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