Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Take into account that the force can be written as follow:
[tex]F=\frac{\Delta p}{\Delta t}[/tex]where,
Δp: change in momentum = 17 kg.m/s
Δt: time interval at which the force change the momentum = 5 s
Replace the previous values of the parameters into the formula for F, and simplify:
[tex]F=\frac{17\operatorname{kg}\frac{m}{s}}{5s}=3.4\operatorname{kg}\frac{m}{s^2}=3.4N[/tex]Then, a force of 3.4N would be needed to change the momentum of an object 17 kgm/s in 5s.
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
