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Sagot :
Answer:
The equation of the line that passes through (-2, 2) and has a slope of -4 in standard form is;
[tex]4x+y=-6[/tex]Explanation:
Given that the line passes through (-2, 2) and has a slope of -4;
[tex]\begin{gathered} m=-4 \\ (x_1,y_1)=(-2,2) \end{gathered}[/tex]Using the point-slope form of linear equation;
[tex]y-y_1=m(x-x_1)[/tex]substituting the given values;
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-2_{}=-4(x-(-2)) \\ y-2=-4(x+2) \\ y-2=-4x-8 \\ \text{moving the terms;} \\ y+4x=-8+2 \\ y+4x=-6 \\ 4x+y=-6 \end{gathered}[/tex]Therefore, the equation of the line that passes through (-2, 2) and has a slope of -4 in standard form is;
[tex]4x+y=-6[/tex]
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