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solve the system of equations below algebraically. state the solution as an ordered pair. Show all work.

Solve The System Of Equations Below Algebraically State The Solution As An Ordered Pair Show All Work class=

Sagot :

We have a system of equations:

[tex]\begin{gathered} x+9=y \\ x=4y-6 \end{gathered}[/tex]

We can solve it by substitution, using the equality of the first equation, replacing y in the second equation:

[tex]\begin{gathered} x=4y-6 \\ x=4(x+9)-6 \\ x=4x+4\cdot9-6 \\ x=4x+36-6 \\ x=4x+30 \\ x-4x=30 \\ -3x=30 \\ x=-\frac{30}{3} \\ x=-10 \end{gathered}[/tex]

With the value of x, we can calculate y as:

[tex]y=x+9=-10+9=-1[/tex]

The solution expressed as ordered pair is (x,y) = (-10,-1).

Answer: (-10, -1)