Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

How strong (in T) is the magnetic field inside a solenoid with 10,400 turns per meter that carries 21.0 A?

Sagot :

Given:

• Number of turns = 10400 turns

,

• Current = 21.0 A

Let's find the strength of the magnetic field.

To find the strength in the magnetic field, apply the formula:

[tex]B=\mu_onI[/tex]

Where:

• B is the magnetic field

,

• μ₀ is the permeability of free space.

,

• n is the number of turns.

,

• I is the current.

Thus, we have:

[tex]B=(4\pi\times10^{-7})*10400*21[/tex]

Solving further, we have:

[tex]B=0.274\text{ T}[/tex]

Therefore, the strength of the magnetic field is 0.274 T.

ANSWER:

0.274 T.

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.