Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

How strong (in T) is the magnetic field inside a solenoid with 10,400 turns per meter that carries 21.0 A?

Sagot :

Given:

• Number of turns = 10400 turns

,

• Current = 21.0 A

Let's find the strength of the magnetic field.

To find the strength in the magnetic field, apply the formula:

[tex]B=\mu_onI[/tex]

Where:

• B is the magnetic field

,

• μ₀ is the permeability of free space.

,

• n is the number of turns.

,

• I is the current.

Thus, we have:

[tex]B=(4\pi\times10^{-7})*10400*21[/tex]

Solving further, we have:

[tex]B=0.274\text{ T}[/tex]

Therefore, the strength of the magnetic field is 0.274 T.

ANSWER:

0.274 T.