Answered

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How strong (in T) is the magnetic field inside a solenoid with 10,400 turns per meter that carries 21.0 A?

Sagot :

Given:

• Number of turns = 10400 turns

,

• Current = 21.0 A

Let's find the strength of the magnetic field.

To find the strength in the magnetic field, apply the formula:

[tex]B=\mu_onI[/tex]

Where:

• B is the magnetic field

,

• μ₀ is the permeability of free space.

,

• n is the number of turns.

,

• I is the current.

Thus, we have:

[tex]B=(4\pi\times10^{-7})*10400*21[/tex]

Solving further, we have:

[tex]B=0.274\text{ T}[/tex]

Therefore, the strength of the magnetic field is 0.274 T.

ANSWER:

0.274 T.

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