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Sagot :
[tex]\begin{gathered} 8x+14y=2 \\ -3x-7y=8 \end{gathered}[/tex]
start by clearing the first equation for x
[tex]\begin{gathered} 8x+14y=2 \\ 8x=2-14y \\ x=\frac{2-14y}{8} \end{gathered}[/tex]insert this equation into the second equation
[tex]\begin{gathered} -3(\frac{2-14y}{8})-7y=8 \\ -\frac{6}{8}+\frac{42}{8}y-7y=8 \\ \frac{42}{8}y-7y=8+\frac{6}{8} \\ -1.75y=8.75 \\ y=-\frac{8.75}{1.75} \\ y=-5 \end{gathered}[/tex]find the value of x
[tex]\begin{gathered} x=\frac{2-14y}{8} \\ x=\frac{2-14(-5)}{8} \\ x=\frac{2+70}{8} \\ x=\frac{72}{8} \\ x=9 \end{gathered}[/tex]The solution for the system of equations is (9,-5)
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