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Sagot :
The given points are
[tex]\begin{gathered} H(-9,3) \\ A(8,-3) \end{gathered}[/tex]We are asked to find the midpoint.
Recall that the midpoint formula is given by
[tex](x,y)=\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}[/tex]We have
[tex]\begin{gathered} x_1=-9 \\ x_2=8 \\ y_1=3 \\ y_2=-3 \end{gathered}[/tex]Substitute the given values into the midpoint formula.
[tex]\begin{gathered} (x,y)=\frac{-9+8}{2},\frac{3-3}{2} \\ (x,y)=\frac{-1}{2},\frac{0}{2} \\ (x,y)=(-\frac{1}{2},0) \end{gathered}[/tex]Therefore, the midpoint of H(-9, 3) and A (8, -3) is found to be
[tex](x,y)=(-\frac{1}{2},0)[/tex]Or it can also be written in the decimal notation as
[tex](x,y)=(-0.5,0)[/tex]
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