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Sagot :
We know that:
- a rocket is launched from the top of an 8-foot ladder.
- It’s initial velocity is 128 feet per second, and it is launched at an angle of 60* with respect to the ground
And we must write parametric equations that describe the motion of the rocket as a function of time
To write the parametric equations we need to know that the parametric general equations for a Projectile Motion are:
[tex]\begin{gathered} x=\left(v_0cos\theta\right)t \\ y=h+\left(v_0sin\theta\right)t-16t^2 \end{gathered}[/tex]Where,
v0 represents the initial velocity
h represents the initial height
θ represents the angle respect to the ground
In our case,
[tex]\begin{gathered} v_0=128\frac{feet}{sec} \\ h=8feet \end{gathered}[/tex]Finally, replacing in the parametric equations:
[tex]\begin{gathered} x=\left(128cos60\degree\right)t \\ y=8+\left(128sin60\degree\right)t-16t^2 \end{gathered}[/tex]ANSWER:
[tex]\begin{gathered} x=(128cos60\operatorname{\degree})t \\ y=8+(128s\imaginaryI n60\degree)t-16t^2 \end{gathered}[/tex]
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