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convert the equation in point-slope form to slope-intercept form:[tex]y - 2 = 3(x - 1)[/tex]

Sagot :

The Slope-Intercept form of the equation of a line is:

[tex]y=mx+b[/tex]

Where "m" is the slope of the line and "b" is the y-intercept.

In this case you have this equation of the line in Point-Slope form:

[tex]y-2=3\mleft(x-1\mright)[/tex]

Then, in order to write it in Slope-Intercept form, you must solve for the variable "y". So you get:

[tex]\begin{gathered} y-2=(3)(x)-(1)(3) \\ y-2=3x-3 \\ y=3x-3+2 \\ y=3x-1 \end{gathered}[/tex]

The answer is:

[tex]y=3x-1[/tex]

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