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The x-intercepts of cosine become what for the secant function?

Sagot :

using the definition of secant we know that,

[tex]sec(x)=\frac{1}{cos(x)}[/tex]

then, the definition of x-intercept is that the function evaluated is equal to 0 then, if f(x) is equal to cos(x)

[tex]f(x)=cos(x)[/tex]

we can say that if the function is equal to 0 then the function secant will look something like this

[tex]\begin{gathered} sec(x)=\frac{1}{0} \\ \end{gathered}[/tex]

and we know that any number divided by 0 is undefined, so the x.intercepts make the function secant undefined, meaning that the x-intercepts become vertical asymptotes in the secant function.

Answer:

The x-intercepts of the function cosine become the vertical asymptotes of the secant function.