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Sagot :
Given:
Resistance, R = 7.17 Ohms
Capacitance, C = 2.59 mF
Inductance, L = 213.91 mH
Frequency, f = 60 Hz
To find:
The phase angle.
Explanation:
The inductive reactance can be calculated as:
[tex]X_L=2\pi fL=2\pi\times60\times213.91\times10^{-3}=80.6422\text{ Ohm}[/tex]The capacitive reactance can be calculated as:
[tex]X_C=\frac{1}{2\pi fC}=\frac{1}{2\pi\times60\times2.59\times10^{-6}}=\frac{1}{9.7640\times10^{-4}}=1024.1404\text{ Ohm}[/tex]The phase angle is given as:
[tex]\varphi=tan^{-1}(\frac{X_L-X_c}{R})=tan^{-1}(\frac{80.6422-1024.1404}{7.17})=-89.56\degree[/tex]Final answer:
The phase angle is -89.56 °.
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