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A series RLC circuit has a resistance of 7.17 ohms, a capacitance of 2.59 mF, and an inductance of213.91 mH. The circuit is connected to a 60 Hz frequency source with a fixed rms output of 63.51 V.• What is the phase angle?

Sagot :

Given:

Resistance, R = 7.17 Ohms

Capacitance, C = 2.59 mF

Inductance, L = 213.91 mH

Frequency, f = 60 Hz

To find:

The phase angle.

Explanation:

The inductive reactance can be calculated as:

[tex]X_L=2\pi fL=2\pi\times60\times213.91\times10^{-3}=80.6422\text{ Ohm}[/tex]

The capacitive reactance can be calculated as:

[tex]X_C=\frac{1}{2\pi fC}=\frac{1}{2\pi\times60\times2.59\times10^{-6}}=\frac{1}{9.7640\times10^{-4}}=1024.1404\text{ Ohm}[/tex]

The phase angle is given as:

[tex]\varphi=tan^{-1}(\frac{X_L-X_c}{R})=tan^{-1}(\frac{80.6422-1024.1404}{7.17})=-89.56\degree[/tex]

Final answer:

The phase angle is -89.56 °.

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