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Find the other endpoint of the line segment with the given endpoint and midpoint.Endpoint: ( 6, 1), midpoint: ( -10, -3)

Sagot :

We know that

• Endpoint: (6, 1)

,

• Midpoint: (-10, -3)​

We use the midpoint formula to find the other end point.

[tex]M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]

Where,

[tex]\begin{gathered} M=(-10,-3) \\ x_1=6 \\ y_1=1 \end{gathered}[/tex]

So, we have to find the coordinates for the second point. Let's replace all given information

[tex](-10,-3)=(\frac{6+x_2}{2},\frac{1+y_2}{2})[/tex]

We solve x-coordinates and y-coordinates separately.

[tex]\begin{gathered} \frac{x_2+6}{2}=-10 \\ x_2+6=-20 \\ x_2=-20-6=-26 \end{gathered}[/tex][tex]\begin{gathered} \frac{y_2+1}{2}=-3 \\ y_2+1=-6 \\ y_2=-6-1 \\ y_2=-7 \end{gathered}[/tex]

Therefore, the other endpoint is (-26, -7).