Answered

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question 2Use 3.14 for pi and round to the nearest tenth

Question 2Use 314 For Pi And Round To The Nearest Tenth class=

Sagot :

Answer:

254.3 cubic mi.

Explanation:

The given composite figure is made up of a cylinder and a hemisphere with the following dimensions:

Cylinder

• Height = 7 mi

,

• Base Radius = 3 mi

Hemisphere

• Base Radius = 3 mi

Thus:

[tex]\begin{gathered} \text{Volume of the composite figure=Vol. of Cylinder+Vol. of Hemisphere} \\ =\pi r^2h+\frac{2}{3}\pi r^3 \end{gathered}[/tex]

Substitute the given values:

[tex]\begin{gathered} V=(\pi\times3^2\times7)+(\frac{2}{3}\times\pi\times3^3) \\ =63\pi+18\pi \\ =81\pi\; =81\times3.14 \\ \approx254.3\text{ }mi.^3\text{ (to the nearest tenth)} \end{gathered}[/tex]

The volume of the composite figure is 254.3 cubic mi.

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