At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Px - 17 = 22 + Qx find the values of P and Q so that the equation has no solution

Sagot :

First, we must combine similar terms. If we move -17 to the right hand side as +17 and Qx to the left hand side as -Qx, we obtain,

[tex]Px-Qx\questeq22+17[/tex]

if we factorize x, we obtain

[tex](P-Q)x=39[/tex]

We can see that the equation has no solution if we obtain a contradictory result.

For instance, if P is equal to Q, we have

[tex]\begin{gathered} 0\cdot x=39 \\ \sin ce\text{ 0 times x is zero, we have} \\ 0=39\text{ !!!} \end{gathered}[/tex]

which is an absurd result. Then, if P = Q the equation has no solution for any x