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A wheel that is initially at rest has forces applied to it, asshown in (Figure 1), and it begins to rotationallyaccelerate.Calculate the net torque about the axle of the wheel. Assume that the friction torque of 0.70 m•N opposes the motion.

A Wheel That Is Initially At Rest Has Forces Applied To It Asshown In Figure 1 And It Begins To RotationallyaccelerateCalculate The Net Torque About The Axle Of class=

Sagot :

Answer:

[tex]\tau_n=4.46m\cdot N[/tex]

Explanation: We need to calculate the net torque, net torque would be the sum of three torques, (1) Clockwise torque (1) Counter-clockwise torque (3) Friction torque.

[tex]\tau_n=\tau_c+\tau_{cc}+\tau_f[/tex]

These three can be calculated from the provided information as follows:

[tex]\begin{gathered} \tau=\tau_c+\tau_{cc}+\tau_f \\ \Rightarrow \\ \tau_c=(35N\times0.12m)+(18N\times0.24M)=8.52m\cdot N \\ \tau_{cc}=(28N\times0.12N)=3.36m\cdot N \\ \tau_f=0.70m\cdot N \\ \end{gathered}[/tex]

The net torque is:

[tex]\begin{gathered} \tau_n=(8.52m\cdot N-3.36m\cdot N)-(0.70m\cdot N)=4.46m\cdot N \\ \therefore\Rightarrow \\ \tau_n=4.46m\cdot N \end{gathered}[/tex]

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