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find the sum of the first n terms of the sequence-8,-32,-128,...; n=10

Sagot :

SOLUTION

In this question, we are meant to find the sum of the first n terms of the sequence.

In this case, n = 10.

Sum of n terms, Sn = a ( r ^n - 1 ) / r - 1 ......... Since the sequence is a Geometric Sequence.

Sn = Sum of n terms

a = first term = - 8

r = common ratio = -32 / - 8 = 4

S10 = -8 ( 4 ^10 - 1 ) / 4 - 1

S10 = -8 ( 1048576 - 1 ) / 3

S10 = -8 X 1048575 / 3

S10 = - 8388600 / 3

S10 = - 2, 796 , 200

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